Like to store all command-line arguments to a bash script into a single variable

Let's say I have a bash script called foo.sh.

I'd like to call it like this

foo.sh Here is a bunch of stuff on the command-line

and I'd like it to store all of that text into a single variable and print it out.

So my output would be:

Here is a bunch of stuff on the command-line

How would I do this?

From stackoverflow

• echo "$*"
  

  would do what you want, namely printing out the entire command-line arguments, separated by a space (or, technically, whatever the value of $IFS is). If you wanted to store it into a variable, you could do

  thevar="$*"
  

  If that doesn't answer your question well enough, I'm not sure what else to say...

  Mark Biek : Easier than I thought. Thanks!

• Have a look at the $* variable. It combines all command line arguments into one.

  echo "$*"
  

  This should do what you want.

  More info here.

• The command echo will take all arguments and print them out:

  echo Here is a bunch of stuff on the command-line
  

  You should quote the arguments if you have special characters.

• If you want to avoid having $IFS involved, use $@ (or don't enclose $* in quotes)

  $ cat atsplat
  IFS="_"
  echo "     at: $@"
  echo "  splat: $*"
  echo "noquote: "$*
  
  $ ./atsplat this is a test
       at: this is a test
    splat: this_is_a_test
  noquote: this is a test
  

  The IFS behavior follows variable assignments, too.

  $ cat atsplat2
  IFS="_"
  atvar=$@
  splatvar=$*
  echo "     at: $atvar"
  echo "  splat: $splatvar"
  echo "noquote: "$splatvar
  
  $ ./atsplat2 this is a test
       at: this is a test
    splat: this_is_a_test
  noquote: this is a test
  

  Note that if the assignment to $IFS were made after the assignment of $splatvar, then all the outputs would be the same ($IFS would have no effect in the "atsplat2" example).